Proof : Let ( A ) and ( B ) be sets. By Pairing, ( A, B ) is a set. By Union, ( \bigcup A, B ) is a set. But ( \bigcup A, B = A \cup B ). QED.
Suppes’ system is (ZF), plus Choice as an optional axiom. This matches most standard mathematics except for pathological choice-dependent results. 8. Sample Theorem and Proof Style Let’s illustrate Suppes’ rigor with a simple theorem from his book: suppes axiomatic set theory pdf
This article explores the structure, axioms, key theorems, and enduring relevance of Suppes’ axiomatic set theory. Before Suppes, set theory had been developed naively by Cantor, Frege, and others. However, the discovery of paradoxes (Russell’s paradox, Cantor’s paradox) showed that unrestricted comprehension leads to inconsistency. The axiomatic approach—pioneered by Zermelo (1908), refined by Fraenkel and Skolem (ZFC)—restricts set formation to avoid contradictions. Proof : Let ( A ) and ( B ) be sets
The axioms are intended to be true statements about the cumulative hierarchy of sets, built in stages (ranks). Suppes’ system is essentially Zermelo–Fraenkel without the Axiom of Choice (ZF), though he discusses Choice separately. Below are the core axioms as presented in his book, rephrased for clarity. Axiom 1: Axiom of Extensionality Two sets are equal iff they have the same members. [ \forall x \forall y [ \forall z (z \in x \leftrightarrow z \in y) \rightarrow x = y ] ] But ( \bigcup A, B = A \cup B )
Suppes’ goal: present a system but with a simpler, more intuitive style, suitable for beginners and philosophers. He uses a first-order language with ε (membership) and = (equality), and builds sets from the empty set upward. 2. The Language and Logical Framework Suppes assumes classical first-order logic with identity. The only non-logical primitive is the binary predicate ∈ (membership). All objects are sets—there are no ur-elements (primitive non-set objects). This is a pure set theory .
Denoted ( \bigcup A ). For any set A, there exists a set whose members are exactly all subsets of A. [ \forall A \exists P \forall x [x \in P \leftrightarrow x \subseteq A] ]
From this we get singletons (when a = b) and unordered pairs. For any set A, there exists a set whose members are exactly the members of members of A. [ \forall A \exists U \forall x [x \in U \leftrightarrow \exists y (x \in y \land y \in A)] ]
