Turbo Physics Grade 12 Pdf Apr 2026

T₂ = T₁ × (P₂/P₁)^((γ-1)/γ)

Density ratio vs. ambient: 1.89/1.18 = 1.60 → 60% more air.

I can’t provide a direct PDF file, but I can give you a that explains turbo physics at a Grade 12 level (ideal gas law, thermodynamics, energy transformations, entropy, and efficiency). You can copy this into a document and save it as a PDF for your studies. Title: The Spool of Adiabat City Chapter 1: The Compressor’s Secret In the industrial sprawl of Adiabat City, where smokestacks kissed condensation trails and pressure gauges dotted every wall, lived a young engineer named Kael. He had just failed his thermodynamics final—the only student who couldn’t explain why a turbocharger worked. turbo physics grade 12 pdf

Kael calculated: Using (η_t = (T₁ - T₂_actual)/(T₁ - T₂_ideal)), he found that 68% of the exhaust’s enthalpy (h = u + Pv) converted into shaft work. The rest became entropy—random molecular motion—which heated the turbine housing.

At 1.8 atm and 135°C (408 K): ρ = (1.8 × 101325 Pa) / (287 J/kg·K × 408 K) ρ ≈ 182385 / 117096 ≈ 1.56 kg/m³ T₂ = T₁ × (P₂/P₁)^((γ-1)/γ) Density ratio vs

T₂ = 298 K × (1.8/1.0)^0.286 T₂ = 298 × 1.8^0.286 1.8^0.286 ≈ 1.178 T₂ ≈ 351 K → 78°C (theoretical ideal).

Power_compressor = ṁ_air × cp_air × (T_out – T_in) / η_mech You can copy this into a document and

“Cooling after compression is like cheating physics,” Kael grinned. “You increase density without losing the work already put in.” The turbo didn’t work instantly. At low RPM, exhaust flow was weak. Kael plotted mass flow rate vs. pressure ratio on a compressor map. The surge line showed where airflow reversed—flutter. The choke line where flow stalled.

But his measured 135°C meant . The compressor efficiency (η_c) = (T₂_ideal – T₁)/(T₂_actual – T₁) = (78-25)/(135-25) = 53/110 ≈ 48%. The rest of the work became heat due to friction and turbulence. Chapter 4: The Density Battle Kael connected the compressor outlet to a small engine cylinder. More air pressure meant more oxygen molecules per volume—but the heat reduced density. Using the ideal gas law rearranged: ρ = P / (R_specific × T)

Using angular dynamics: τ = I × α, where τ = torque from turbine, I = rotational inertia, α = angular acceleration.